Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Provided the 2% interest rate. The interest itself over a period of 4 years, compounds to $300. Thus, the total interest plus the cost of the fitness equipment would be a total of, $4,050.
Answer:
21
Step-by-step explanation:
The <em><u>correct answers</u></em> are:
Angle A is congruent to angle E; and BC=FD.
Explanation:
For ASA, we want two angles and an included side of one triangle congruent to two angles and an included side of the other triangle. The sides we have marked are AC and DE; the angles already marked congruent are C and D. In order to be ASA, the other angle must be on the other side of the congruent side; this means that we have angles A and E.
For SAS, we want two sides and an included angle of one triangle congruent to two sides and an included angle of the other triangle. We have angles C and D congruent and sides AC and DE congruent. In order to be SAS, the other side must be on the other side of the congruent angle; this means we have sides BC and FD.
Answer:
6
Step-by-step explanation:
6.5 lined up to x is 6