a)
Check the picture below.
b)
volume wise, we know the smaller pyramid is 1/8 th of the whole pyramid, so the volume of the whole pyramid must be 8/8 th.
Now, if we take off 1/8 th of the volume of whole pyramid, what the whole pyramid is left with is 7/8 th of its total volume, and that 7/8 th is the truncated part, because the 1/8 we chopped off from it, is the volume of the tiny pyramid atop.
Now, what's the ratio of the tiny pyramid to the truncated bottom?
Answer:
70.7 ft
Step-by-step explanation:
The triangle formed by home plate, first base, and second base is an isosceles right triangle with hypotenuse 100 ft. Then the side length (base-line distance between bases) is (100 ft)/√2 ≈ 70.7 ft.
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For an isosceles right triangle with side lengths 1, the hypotenuse can be found from the Pythagorean theorem to be ...
hypotenuse = √(side² + side²) = √(1²+1²) = √2
Then the diamond distances satisfy the proportion ...
hypotenuse/side = 100 ft/(base distance) = √2/1
or ...
base distance = (100 ft)/√2 ≈ 70.71068 ft
4x^2 - 36 = 0
4x^2 = 36
x^2 = 9
x = 3 or -3
the answer is C
(2x24)+(2x42)
I am not sure
