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trapecia [35]
3 years ago
11

A(n) __________ (rational / irrational) number answer is desired.

Mathematics
2 answers:
Andrej [43]3 years ago
8 0

Answer:

it's irrational because irrational has to be irrational

Vesna [10]3 years ago
4 0
Is there options for this question? I dont understand what your asking. 
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(25 points) A weather reporter in your area said that the speed of sound in air today is about one thousand one hundred feet per
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2 years ago
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0
2 years ago
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