Both 17/10 and 2 4/5 should be rounded up in preparation for this estimation.

17/10 is close to 2 and 2 4/5 is close to 3. Thus, your estimated answer should be
2/3, or approx. 0.6666....

Exact answer: divide 17/10 by 14/5. LCD is 10, so convert 14/5 to 28/10.

Now divide 17/10 by 28/10. Answer: 17/28 = approx. = 0.607 approx.

These two results are comparable: 0.6666.... and 0.6071 ....

8 0

3 years ago

What is 7+10x-2x-2=-3

Ivahew [28]

7+10x-2x-2=-3

—-Combine like terms...10x-2x=8x and 7-2=5

8x+5=-3
——subtract 5 on both sides.. the 5’s will cancel each other and -3-5=-8

8x=-8
——Divide 8 on both sides...the 8’s will cancel out and -8 divided by 8 = -1

Answer: x = -1

6 0

3 years ago

Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per

Otrada [13]

Answer: (0.8115, 0.8645)

Step-by-step explanation:

Let p be the proportion of people who leave one space after a period.

Given: Sample size : n= 525

Number of people responded that they leave one space. =440

i.e. sample proportion: $\hat{p}=\dfrac{440}{525}\approx0.838$

z-score for 90% confidence level : 1.645

Formula to find the confidence interval :

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$0.838\pm (1.645)\sqrt{\dfrac{0.838(1-0.838)}{525}}\\\\=0.838\pm (1.645)\sqrt{0.00025858285}\\\\=0.838\pm (1.645)(0.01608)\\\\= 0.838\pm0.0265\\\\=(0.838-0.0265,\ 0.838+0.0265)\\\\=(0.8115,\ 0.8645)$

Hence, a 90% confidence interval for the proportion of people who leave one space after a period: (0.8115, 0.8645)

3 0

3 years ago