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Cloud [144]
4 years ago
15

Samantha wants to use her savings of 1150 to buy shirts and watches for her family. The total price of the shirt she bought was

$84. The watches cost $99 each what is the maximum number of watches that Samantha come by with her savings?
Mathematics
1 answer:
ioda4 years ago
8 0

<u>Answer-</u>

<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>

<u>Solution-</u>

The amount of money Samantha has in her savings account = $1150

She wants to buy shirts and watches.

Cost of one shirt = $84

Cost of each watch = $99

Let she can buy maximum of x watches, so the net price of the watches is $99x.

Then,

\Rightarrow 99x+84=1150\\\\\Rightarrow 99x=1150-84\\\\\Rightarrow 99x=1066\\\\\Rightarrow x=\dfrac{1066}{99}\\\\\Rightarrow x=10.77

As the number of watches can not be in fraction, so at most she can buy 10 watches.

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You can use the formula for getting the xth term of a geometric sequence for the graphed points.

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Option A:  f(x) = 80 \times (\dfrac{1}{4})^{x-1}

<h3>What is  a geometric sequence and how to find its xth terms?</h3>

There are three parameters which differentiate between which geometric sequence we're taking about.

  • The first parameter is the initial value of the sequence.
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Suppose the initial term of a geometric sequence is  a and the term by which we multiply the previous term to get the next term is  r

Then the sequence would look like

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Thus, the xth term of such sequence would be

f(x) = \text{xth term} = ar^{x-1}

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The points plotted in the graph are

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The x coordinate shows the position of the term and the y coordinate shows the value of that position's term in the sequence.

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Thus, by using the xth term formula, we have:

f(x) = \text{xth term} = ar^{x-1} = 80 \times (\dfrac{1}{4})^{x-1}\\\\f(x) = 80 \times (\dfrac{1}{4})^{x-1}

Thus,

The function that represents the graphed geometric sequence is given by

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