The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.
Ways of having 17:
Die 1 Die 2 Die 3 sum
6 6 5 6+6+5 = 17
6 5 6 6+5+6 = 17
5 6 6 5+6+6 = 17
Those are the only 3 possibilities of having 17 (you can only loose 1 point).
The total number of outcomes are 6*6*6 = 216
So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139
the answer is 5.10729613...
Answer:
0.4
Step-by-step explanation:
just add a cero mi uyrhv de ryu.
Answer:
I think it is A.
Step-by-step explanation:
Hope my answer has helped you!
Answer:
Remaining: n-m/n *100 Used m/n* 100
Step-by-step explanation:
