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lesya [120]
3 years ago
11

Substitute the given values into the given formula and solve for the unknown variable. If necessary, round to one decimal place

Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

T = Time = 3 years

Step-by-step explanation:

1 = PRT;

1 = Simple Interest = 5040

P = Principal = 24,000

R = Rate = 0.07

T = Time (years) = ? Unknown variable

Making T subject of the formula

T = 1/PR

T = 5040/24,000 × 0.07

T = 5040/1680

T = 3 years

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garik1379 [7]

B is the answer

i simplified the theorem, but i hope this makes sense!

3 0
2 years ago
Read 2 more answers
Please help.
Alika [10]

Answer:

250 smaller boxes

Step-by-step explanation:

Find the volume of the 2 cuboids.

Formula = Length x width x height

Big cuboid = 50 x 30 x 20 = 30000

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30000 ÷ 120 = 250 small boxes

5 0
3 years ago
Write these fractions in least common denominator2/5x+15y 1/2x+6y
Over [174]
Look at deonomators

assuming that the deonomenators are 5x+15y and 2x+6y

find their LCM
factor

5x+15y=5(x+3y)

2x+6y=2(x+3y)

LCM=10(x+3y)=10x+30y

multiply 2/(5x+15y) by 2/2=4/(10x+30y)
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if we add them
9/(10x+30y)
3 0
3 years ago
The life expectancy (in hours) of an electric bulb is normally distributed with a mean of 5000 and a standard deviation of 1000.
Sergeu [11.5K]

Answer:

P(z>1.3) = 0.9032

Step-by-step explanation:

We are given:

Mean = 5000

Standard deviation = 1000

x = 6300

P(x>6300)=?

z-score =?

z-score = x- mean/standard deviation

z-score = 6300 - 5000/1000

z- score = 1300/1000

z-score = 1.3

So, P(x>6300) = P(z>1.3)

Looking at the z-probability distribution table and finding value:

P(z>1.3) = 0.9032

So, P(z>1.3) = 0.9032

7 0
4 years ago
Please help me with number 1, thanks
tekilochka [14]
What don't you get about the problem ?
5 0
3 years ago
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