No they are not… not the same size
Answer: 15 units .
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In this case, a square, the two sides of the square (forming a right triangle) are equal), and the "diagonal" forming is the hypotenuse of the right triangle.
In these cases, the measurements of the angles of the right triangle are "45, 45, 90" ; and the measurements of the sides are: "a, a, a√2" ; in which "a√2" is the hypotenuse.
We are given: "15√2" is the hypotenuse" ; and we are given that this is a right triangle of a square with a diagonal length (i.e. "hypotenuse" of "15√2" ; so the measure of the side of the "square" (and other two sides of the triangle formed) is: 15 units. (i.e., 15, 15, 15√2 ).
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
7 - 2 (7) -8
7 - 14 - 8
7-14= -7
-7 - 8 = - 15
May have messed this one up
first subtract the last equation from the first. this gives:-
-x + y = -8 .....................(1)
Then multiply the first equation by 2 and add it to the 2nd equations This gives
9x = 18
so x = 2
and from equation (1) y = -8 + 2 = -6
Substituting for x and y in the second equation
z = (24 -5(2) -12) / 2 = 1
Answer is choice b.
