the length of the two legs of a right triangle are 2 square root 3 and 5 what is the length of the hypotenuse
1 answer:
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Answer: {5, -7, -19, -27, -35}
Step-by-step explanation:
In order solve this, we need to plug in the values of x into the table.
For spaces on the left of the equals sign, you need to write each x from the domain. You can then match that x-value with its function value by putting that on the right side.
For each equation, we are simply plugging a number from the domain into the function and replacing the x-value:
I hope this helps. If you need any extra explanation on how the functions are set up, please let me know.
The given operation involves just swapping the two rows, so carrying out 
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)