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2 years ago

What is 127 divisble by

Mathematics

1 answer:

Svet_ta [14]2 years ago

8 0

Any thing above 13

127= a prime number

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Which statement best illustrates using the vertical line test to determine if the graph below is a function of X? ANSWER FAST IL

MaRussiya [10]

Answer:

The graph is nor a function og x because tha like y=0 intersects the graph at two points

7 0

2 years ago

Help ASAP Pythagorean tyoerem

marin [14]

Answer:

Step-by-step explanation:

Sides opposite to equal angles are equal.

x = 8

Pythagorean theorem,

y² = 8² + 8²

= 64 + 64

y² = 128

y = √128

y = 11.31

4 0

2 years ago

3х + 1 = -11 What is the answer?

Fiesta28 [93]

Answer:

-4

Step-by-step explanation:

3x+1=-11

-1 -1

3x=-12

/3 /3

x = -4

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2 years ago

Read 2 more answers

What is X divided by 5 if X=5?

Paraphin [41]

If you divide X which is 5 by 5, then you will get 1.

5^1 will be 5.

5 divided by 0 does not have a solution. It is not a number.

It is possible to subtract an integer with a negative sign from another number, for example 5-(-3). Multiplying two negative signs will make the sign positive, so the problem would then be this: 5+3. That equals 8.

1+1-1x1/1= 1

7 0

3 years ago

It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random

Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

$\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9$

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample t-test will be used.

The correct option is b.

(2)

The null hypothesis is:

H₀: The average temperature in the population is 98.6°F, i.e. μ = 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

Hₐ: The average temperature in the population is less than 98.6°F, i.e. μ < 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

$SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F$

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

$t=\frac{\bar x-\mu}{SD_{\bar x}}$

$=\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67$

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

= 9 - 1

= 8

Thus, the degrees of freedom of the test is 8.

8 0

3 years ago