What is 127 divisble by

Divide the given polynomial by the given monomial.

yanalaym [24]

Answer:

Here are the answers. Need to have 20 characters for answer. Phew

6 0

2 years ago

HELP WILL MARK BRAINLIEST!!!!!!!

zlopas [31]

Answer and Step-by-step explanation:

4 hours on Monday, so subtract 4 from 16.

We get 12.

So now it says twice as many on Saturday as on Thursday

So two numbers that add up to 12, but one number is twice the other number, would be 4.

4 times 2 is 8, and 4 + 8 is 12. 12 + 4 = 16

8 is the answer.

Kyle works 8 hours on Saturday.

Since 8 is twice the amount of 4, and 8 + 4 + 4 equals 16.

#teamtrees #PWA (Plant And Water)

4 0

2 years ago

If K = {(x, y)|x - y = 5}, find the corresponding range of y for the domain {0, 2, 4}. {-5, -3, -1} {0, 2, 4} {5, 7, 9}

Aleks04 [339]

Answer:

The range = {-5 , -3 , -1} ⇒ first answer

Step-by-step explanation:

* In any equation the values of x are the domain of it and

the values of y are the range of it

* So to find the range of any equation substitute the values

of x (domain) in the equation to get the corresponding

values of y (range)

* In the problem

∵ K = {(x , y): x - y = 5}

∵ The domain is {0 , 2 , 4}

* Lets find K(0) , K(2) , K(4)

∵ K(0) = (0) - y = 5

∴ -y = 5 ⇒ Multiply both sides by -1

∴ y = -5

∵ K(2) = (2) - y = 5

∴ 2 - y = 5 ⇒ subtract 2 from both sides

∴ -y = 3 ⇒ Multiply both sides by -1

∴ y = -3

∵ K(4) = (4) - y = 5

∴ 4 - y = 5 ⇒ subtract 4 from both sides

∴ -y = 1 ⇒ Multiply both sides by -1

∴ y = -1

* The range = {-5 , -3 , -1}

8 0

3 years ago

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(w+2t)(w^2-2wt+4t^2)

viktelen [127]

Multiply w with every term in the second parenthesis:
w³-2w²t+4wt²
multiple 2t with every term in the second parenthesis:
2w²t-4wt²+8t³
add up the products: w³+8t³

8 0

3 years ago

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Rita is selecting a sandwich at the deli. The deli has four types of meat, three types of cheese and two types of bread. A delux

zalisa [80]

Answer:

24 possible dishes

Step-by-step explanation:

Given

Total

$Meat = 4$

$Cheese = 3$

$Bread = 2$

Selection

$Meat = 1$

$Cheese =2$

$Bread = 1$

Required

Determine the number of possible combo

Rita wants to select 1 of 4 meat types,

So, the number of selections is: $^4C_1$

Rita wants to select 2 of 3 cheese types,

So, the number of selections is: $^3C_2$

Rita wants to select 1 of 2 cheese types,

So, the number of selections is: $^2C_1$

The total number of selections is:

$Total = ^4C_1 * ^3C_2 * ^2C_1$

Using

$^nC_r = \frac{n!}{(n-r)!r!}$

We have:

$Total = \frac{4!}{(4-1)!1!} * \frac{3!}{(3-2)!2!} * \frac{2!}{(2-1)!1!}$

$Total = \frac{4!}{3!1!} * \frac{3!}{1!2!} * \frac{2!}{(1!1!}$

$Total = \frac{4*3!}{3!*1} * \frac{3*2!}{1*2!} * \frac{2*1}{1*1}$

$Total = 4* 3 * 2$

$Total = 24$

Hence, there are 24 possible dishes

4 0

3 years ago

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