Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
Step-by-step explanation:
EF = 6x - 4
and it is also the combination of EG and GF.
so,
6x - 4 = EG + GF = EG + 13
6x = EG + 17
now, we have additional information. EF bisects CD. that means it cuts CD in half.
and that means both banks must be off equal size.
5x - 1 = 7x -13
12 = 2x
x = 6
so, back to the first problem
6×6 = EG + 17
36 = EG + 17
19 = EG
