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bija089 [108]
3 years ago
6

Find the surface area of a sphere with a volume of 33.51 cubic inches

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r = radius\\ \cline{1-1} V=33.51 \end{cases}\implies 33.51=\cfrac{4\pi r^3}{3}\implies 100.53 = 4\pi r^3 \\\\\\ \cfrac{100.53}{4\pi }=r^3\implies 7.9999 \approx r^3\implies 8\approx r^3\implies \sqrt[3]{8}\approx r\implies \boxed{2 \approx r} \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies SA\approx4\pi \left( \boxed{2} \right)^2\implies SA\approx16\pi \implies SA\approx 50.27

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<h3>How to identify if a triangle is acute?</h3>

Let us have:

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Two sides of an acute triangle measure as 5 inches and 8 inches

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WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

A^2 + B^2 < C^2

Here in this sum,

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2 years ago
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3 years ago
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