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svet-max [94.6K]
3 years ago
15

write a division problem that has a 3-digit dividend and a divisor beteen 10 and 20 show how to solve with a quick picture

Mathematics
1 answer:
stich3 [128]3 years ago
5 0
665/15. my answer bshsjakakkwjauz
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A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.
kondor19780726 [428]

Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that N = 8 + 10 = 18

We want 3 boys, so k = 8

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that n = 8

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

3 0
3 years ago
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