Missing Details of Question
Statistical multiplexing is used, with details as follows o
- Packet Payload Size = 1000 Bytes
- Packet Header Size = 24 Bytes (overhead)
- Ignore Processing and Queueing delays
- Assume partial packets (packets consisting of less than 1000 Bytes of data) are padded so that they are the same size as full packets.
- Assume continuous alternating-packet transmission.
Answer:
Time = 10.47
Explanation:
Given
Initial Time, t = 0
File X = 14MiB = 14 * 1024 * 1024 = 14,680,064 bytes
File Y = 272KiB = 272 * 1024 = 278528 bytes
Transmission Rate = 11.7Mbps
Total Packet Length is calculated as (1024 * 8)/(11.7Mbps)
Total Packet Length = 8192 ÷ 11700
Total Packet Length = 0.700171 ms/packets
Number of packets
File X = 14,680,064 bytes ÷ 1000 bytes
File X = 14,680.064
File X = 14,680 ---- Approximated
File Y = 278528 bytes ÷ 1000 bytes
File Y = 278.528
File Y = 279 ------- Approximated
Number of Packets = 279 + 14,680
= 14959 packets
The implication of the above is that, File X after a total of 20202 packets are transmitted
File Y will finish transmitting at:
14959 * 0.700171
= 10473.86 ms
= 10.47386 s
= 10.47 s
