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Serhud [2]
3 years ago
12

Where (what memory location) is the data read from for the following code:

Computers and Technology
1 answer:
alexdok [17]3 years ago
6 0

Answer: ORG $3000 tell us that we want to load the program from the address $3000.

LDAA #$C2 tell us to load the value contained in the address present in the register C2 into the accumulator.

Explanation:

ORG instruction in  microprocessor does not have a fixed address. It tell us where to begin the execution of the program by loading into a starting address space. It does not uses fixed addressing

LDAA instruction uses indirect addressing by placing the value from the address present in the register. Here  the address is contained in register C2.

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Answer: Auto correct

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Write the class RoadSegmet. The class inherits from Transportation Class. The Class have a vector hourlySpeeds data field which
OLEGan [10]

Answer:

The length of time on the road segment is calculated by taking it's distance and dividing by the speed at the time of departure. This length of time is then added to the departureTime parameter to get the arrivalTime.

Define a RiverSegment class that inherits from the base TransportationClass from above. This class will have a vector<double> scheduledDepartureTimes data field that will keep track of the departure time (e.g. 10.5 represents the time 10:30) of all ferries on the river. You can assume these are sorted. Additionally, there is a _speed value that is the speed of the ferry at all times (ferries tend to be consistently slow). There is a setSpeed function to change the _speed value. Additionally, there is an addDepartureTime(double hour) function to add a departure time to the vector. Make sure the time are sorted

Computing the arrival time for the RiverSegment is a little more complicated since you need to wait for the next available departure time. Once you find the next available departure time (after the departure time passed in), you need to add the length of time on the river segment. This is done by dividing the _distance by the _speed. Add the time on the river to the departure time (from the vector of departure times) and this will give you the arrive time.

note: If there is no departure time scheduled for after your planned departure, you need to take the first available departure the following day. Our solution assumes the departure times are the same every day.

TransportationLink.h

#include <string>

using namespace std;

#ifndef __TRANSPORTATIONLINK_H__

#define __TRANSPORTATIONLINK_H__

const int HOURS_PER_DAY = 24;

const int MINS_PER_HOUR = 60;

const int MINS_PER_DAY = MINS_PER_HOUR * HOURS_PER_DAY; //24 * 60

class TransportationLink {

protected:

string _name;

double _distance;

public:

TransportationLink(const string &, double);

const string & getName() const;

double getDistance() const;

void setDistance(double);

// Passes in the departure time (as minute) and returns arrival time (as minute)

// For example:

// 8 am will be passed in as 480 (8 * 60)

// 2:30 pm will be passed in as 870 (14.5 * 60)

virtual unsigned computeArrivalTime(unsigned minute) const = 0;

};

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3 years ago
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10 computer and operating systems errors​
babunello [35]

Answer:

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Explanation:

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

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           System.out.println(bag_ounces+" seconds");

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   }

Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

       print_popcorn_time(bagOunces);

   }

   public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

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       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

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