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harina [27]
3 years ago
7

Can anyone help me pls

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0
5-4*9= 9
just use the properties
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The A store has the price for 2/$ 5 and the B one has 5.99 who should i buy from and why?
Aloiza [94]
You should purchase from the store that is selling the 2/$5. You spend less money per item. The A store has you pay $2.50 per item with the deal while the B store has you pay almost $6 per item.
3 0
3 years ago
Marcos is mixing a solution in science class. He is mixing 3 ounces of food coloring with every 8 ounces of water. If he wants a
jonny [76]

Answer:

With the 24 ounces of water he would have 9 ounces of food coloring.

Step-by-step explanation:

For ever 8 ounces of water there is 3 ounces of food coloring so if there is 24 ounces of water that mean there is 3 times the original starting amount. So 8x3=24 so there is 24 ounces of the water. Since the8 got multiplied by 3 that means the 3 we haven't used yet will get multiplied by 3 as well so we can find the answer. So 3x3=9. That means we would have 9 ounces of food coloring with the 24 ounces of water.

7 0
3 years ago
5/6 - 1/3 x 7/8<br><br> (The x is multiplication)
12345 [234]
5/6 - 1/3 × 7/8
5/6 - 7/24
20/24 - 7/24
13/24

do the multiplication first
4 0
3 years ago
Find the length of<br> __<br> JK<br> Round answer to nearest tenth.
PIT_PIT [208]

Answer:

Step-by-step explanation:

We would apply the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes

JK² = JL² + KL² - 2(JL × KL)Cos10

JK² = 61² + 53² - 2(61 × 53)Cos10

JK² = 3721 + 2809 - 6466Cos10

JK² = 6530 - 6367.767

JK² = 162.233

Taking square root of both sides of the equation, it becomes

JK = √162.233

JK = 12.73 to the nearest tenth

6 0
3 years ago
This is 13 points plz help ( no links ) explain your answer plz<br> ( only answer if u know it )
umka21 [38]
The answer is 960 :)
4 0
3 years ago
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