Step-by-step explanation:
If you need help with how I got my answer, you can ask me.





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The angle between two vectors is given by:
cos (x) = (v1.v2) / (lv1l * lv2l)
We have then:
v1.v2 = (2, -5). (4, -3)
v1.v2 = (2 * 4) + (-5 * (- 3))
v1.v2 = 8 + 15
v1.v2 = 23
We look for the vector module:
lv1l = root ((2) ^ 2 + (-5) ^ 2)
lv1l = 5.385164807
lv2l = root ((4) ^ 2 + (-3) ^ 2)
lv2l = 5
Substituting values:
cos (x) = (23) / ((5.385164807) * (5))
x = acos ((23) / ((5.385164807) * (5)))
x = 31.33 degrees
Answer:
The angle between the two vectors is:
x = 31.33 degrees





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Answer:
1080 m^2 Don't submit m^2 in your answer.
Step-by-step explanation:
Givens
The catch is to find h
To do that, use a^2 + b^2 = c^2
a b and c are in the same 1/2 triangle.
a = 48/2 = 24 m
b = h = ?
c = 51 meters
Solution
a^2 + b^2 = 51^2 Substitute for b^2 = h^2
24^2 + h^2 = 51^2 Expand 24^2 and 51^2
576 + h^2 = 2601 Subtract 576 from both sides
h^2 = 2601 - 576
h^2 = 2025 Take the square root of both sides
h = 45
Area
Area = 1/2 b * h
Area = 1/2 48 * 45
Area = 1080
Remark
Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.
To find the area, you need to use all of 48 because 48 is the full length of the base.