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3 years ago

Find the indicated one-sided limit, if it exists:

1 answer:

8 0

The main point which will immediately make it clear is that you have to plug in 2 for x so that you can find the linit. So, using this simple method you will get the -1/4 answer. Hope you will agree with me and find this useful! Regards.

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Make n the subject of the formula

kogti [31]

Answer:

$\mathsf{ \frac{m + 21}{5} = n }$

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

there's a "-21" next to "5n", inverse of subtraction is addition, so add 21 on both sides of the equation.

=> m + 21 = 5n - 21 + 21

=> m+ 21 = 5n

There's also a 5 attached to n, that means the multiplication of n with 5, the inverse of multiplication is division, so dividing both sides of the equation by 5

$\mathsf{ \frac{m + 21}{5} = n }$

3 0

3 years ago

Tell whatever the ordered pair is a solution of the given system.

bagirrra123 [75]

1. No 2. Yes 3. No
I’m pretty sure

5 0

3 years ago

An educator wants to determine whether early exposure to school will affect IQ. He enlists the aid of the parents of 12 pairs of

Anon25 [30]

A____________________

8 0

3 years ago

Solve for the inequality? A OR B?

ASHA 777 [7]

Step-by-step explanation:

3x - x = 2x

2(x + 2) = 2x + 2

for every number of x, 2x + 2 would always be larger than 2x.

so there is no solution, since the given equation is 2x is greater than 2x + 2.

6 0

2 years ago

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Use the equation 0 = ?16t2 + 38

mario62 [17]

Answer:

t = 2.5 s

Step-by-step explanation:

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :

$16t^2 + 38.8t + 3 =0$

The above equation is a quadratic equation. The general equation is :

$ax^2+bx+c=0$

Here, a = 16, b = 38.8 and c = 3

The solution of quadratic equation is given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\t=\dfrac{-38.8\pm \sqrt{(38.8)^2-4\times (-16)\times 3} }{2\times (-16)}\\\\t=\dfrac{-38.8+\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}, \dfrac{-38.8-\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}\\\\t=-0.075\ s,2.5\ s$

So, at t = 2.5 s the balloon is in air.

8 0

3 years ago