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son4ous [18]
3 years ago
7

Please help me with this

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer: a=4, b=-8, c=-3

Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.

The standard form is ax^2+bx+c.

A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).

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If a rectangle's length is 7 more than 4 times the width and the perimeter is 54 what are the dimensions of the rectangle?
Rus_ich [418]
Let w = width of the rectangle 
<span>4w+7 = length of the rectangle </span>

<span>perimeter = 2 lengths + 2 widths </span>

<span>2w + 2(4w+7) = 54 </span>
<span>2w + 8w + 14 = 54 </span>
<span>10w = 40 </span>
<span>w = 4 </span>
<span>4w+7 = 23 </span>

<span>dimensions of rectangle: </span>
<span>width = 4 </span>
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