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nataly862011 [7]
3 years ago
15

10 POINTS!!!!! Which of the following statements is true about 63 and 20?

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
6 0
Hello there!

The correct answer is A
They are relatively prime


I hope that helps!
uysha [10]3 years ago
4 0
The answer is: A) They are relatively prime. This is because both of them aren't divisible by any other number than 1. (or 0 if you really want to do that)
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A physics class is building a bottle rocket. Last week, it flew for 26.189 seconds. This week, it flew for 34.9 seconds. How muc
fredd [130]

Answer:

26.189 - 34.9

Step-by-step explanation:

26.189 - 34.9 = 8.711

8 0
3 years ago
What are the greatest common divisors of these pairs of integers?a. 3⁷. 5³. 7³,2ⁱⁱ.3⁵.5⁹b. 11.13.17, 2⁹.3⁷.5⁵.7³c. 23³ⁱ,23ⁱ⁷d. 4
KatRina [158]

Answer:

a) 3⁵5³.

b) 1

c) 23³

d) 41·43·53

e) 1

f) 1111

Step-by-step explanation:

The greatest common divisor of two integers is the product of their common powers of primes with greatest exponent.

For example, to find gcd of 2⁵3⁴5⁸ and 3⁶5²7⁹ we first identify the common powers of primes, these are powers of 3 and powers of 5. The greatest power of 3 that divides both integers is 3⁴ and the greatest power if 5 that divides both integers is 5², then the gcd is 3⁴5².

a) The greatest common prime powers of 3⁷5³7³ and 2²3⁵5⁹ are 3⁵ and 5³ so their gcd is 3⁵5³.

b) 11·13·17 and 2⁹3⁷5⁵7³ have no common prime powers so their gcd is 1

c) The only greatest common power of 23³ and 23⁷ is 23³, so 23³ is the gcd.

d) The numbers 41·43·53 and 41·43·53 are equal. They both divide themselves (and the greatest divisor of a positive integer is itself) then the gcd is 41·43·53

e) 3³5⁷ and 2²7² have no common prime divisors, so their gcd is 1.

f) 0 is divisible by any integer, in particular, 1111 divides 0 (1111·0=0). Then 1111 is the gcd

5 0
3 years ago
Which two doesn’t belong? PLEASE HELP!! I will give a thanks!!!
stich3 [128]
The 2 blue parallel lines because they are parallel :)
4 0
2 years ago
A company plans to build a wheelchair ramp with the following
Liono4ka [1.6K]

9514 1404 393

Answer:

  yes

Step-by-step explanation:

The height that would be allowed with a ramp 43.5 feet long is ...

  h = (43.5 ft)·sin(4.8°) ≈ 3.64 ft

The proposed height is less than 3.64 ft, so the ramp angle is less than 4.8°.

__

The ramp angle is actually arcsin(3/43.5) ≈ 3.95°, which is less than 4.8°.

7 0
3 years ago
Write the function f(x) = 3x2 - 6x + 5 in vertex
weeeeeb [17]
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
7 0
2 years ago
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