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3 years ago

10 POINTS!!!!! Which of the following statements is true about 63 and 20?

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

6 0

Hello there!

The correct answer is A
They are relatively prime

I hope that helps!

uysha [10]3 years ago

4 0

The answer is: A) They are relatively prime. This is because both of them aren't divisible by any other number than 1. (or 0 if you really want to do that)

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Brayden signed up for a streaming music service that costs $11 per month. The service allows Brayden to listen to unlimited musi

Vsevolod [243]

s = # of songs

y = total amount of money

$11 + $1(35) = y

Simplify the right side

$11 + $35 = y

Combine like terms

$46 = y

If he downloaded 35 songs, he would have ti pay $46

If he downloaded s amount of songs, he would have to pay $11 + $1s = y

4 0

3 years ago

Ronnie swims 4 laps each day at the pool.how many laps does he swim in 28 days?

pishuonlain [190]

Answer:

the answer is 92.

Step-by-step explanation:

do 28 times 4, 28 for the days and 4 for the total laps each day.

8 0

2 years ago

Derek was 4 years 2 months old when he joined school. Today he is 11 years 1 month old. For how long has he been in school?

lora16 [44]

Answer:

Step-by-step explanation:

first of all,we should do this:

1 year is 12 month

amd 4 year is 48 month(12×4)

then we must add 2 months (wich is given) to 48

He was 50 months old when he started school

and we should find how old is he now

11 ×12=132months

132+1=133months

133-50=83 ( he has been 83 months in school)

let's turn it to years 6 years 11 months

( for finding years you should divide 83 to 12)

hope it helps

6 0

2 years ago

A culture started with 5000 bacteria after 5 hours it grew to 6500 bacteria predict how many bacteria will be present after 16 h

postnew [5]

Answer:

After 16 hours bacterial count will be 11600.

Step-by-step explanation:

Bacterial growth is always an exponential growth in a given culture.So the formula for the growth will be

Final counts of bacteria = Initial counts × $(rate of growth)^{time}$

Given from first part Initial counts = 5000

Final counts= 6500 and time of growth = 5 hours

Then we will get the value of rate of growth of bacteria from the bacteria

⇒ 6500 = 5000× $(rate)^{5}$

$(rate)^{5}= \frac{6500}{5000} = 1.3$

$Rate = \sqrt[5]{1.3} = 1.05$

Now again to get the value of bacteria after 16 hours

Final Count = 5000× $(1.05)^{16}$

= 5000×2.32

= 11600

7 0

3 years ago

Help, i've been trying for around 30mins and I can't figure it out.

omeli [17]

Answer:

<h2>Option A and C</h2>

Step-by-step explanation:

As,

$2 \sqrt{75} + 3 \sqrt{50}$

$= 2 \sqrt{25 \times 3} + 3 \sqrt{25 \times 2} (A)$

$= 2 \times 5 \sqrt{3} + 3 \times 5 \sqrt{2}$

$= 10 \sqrt{3} + 15 \sqrt{2} (C)$

6 0

3 years ago

Read 2 more answers