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astraxan [27]
3 years ago
7

Hello 10+5+16+4 = ?? hellpp​

Mathematics
2 answers:
algol133 years ago
6 0

Answer:

30

Step-by-step explanation:

joja [24]3 years ago
4 0
Answer: 10+5+16+4=35
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Solve <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20-%205" id="TexFormula1" title="y = {x}^{2} - 5
vesna_86 [32]

Add 5 to both sides

y + 5 = x^2

Take the square root of both sides

±√y + 5 = x

Switch sides

<u>x = ±√y + 5</u>

3 0
3 years ago
When seven times a number is deceased by 3, the result is 25. What is the number?
zepelin [54]

7n-3= 25

7n-3(+3)= 25(+3)

(7n= 28)/7

n=4

6 0
3 years ago
Read 2 more answers
A cylinder has a base diameter of 20 meters and a height of 10 meters. What is it’s volume in cubic meters, to the nearest tenth
Korvikt [17]

3141.6 cubic meters

Step-by-step explanation:

The volume of a cylinder is given by;

πr²h

π * (²⁰/₂)² * 10

π * 100 * 10

= 3141.6

4 0
4 years ago
Give an example of a function f : N → N that is surjective but not injective. You must explain why your example is surjective an
Helen [10]

Answer:

Consider f: N → N defined by f(0)=0 and f(n)=n-1 for all n>0.

Step-by-step explanation:

First we will prove that f is surjective. Let y∈N be any natural number. Define x as the number x=y+1. Then x∈N, and f(x)=x-1=(y+1)-1=y.  We conclude that f is surjective.

However, f is not injective. Take x1=0 and x2=1. Then x1≠x2 but f(x1)=0 and f(x2)=x2-1=1-1=0. We have shown that there are two natural numbers x1,x2 such that x1≠x2 but f(x1)=f(x2), that is, f is not injective.

Note:

If 0∉N in your definition of natural numbers, the same reasoning works with the function f: N → N defined by f(1)=1 and f(n)=n-1 for all n>1. The only difference is that you consider x1=1, x2=2 for the injectivity.

7 0
3 years ago
A pizza parlor offers 3 sizes of pizzas, 2 types of crust, and one of 4 different toppings. How many different pizzas can be mad
KonstantinChe [14]

Answer:  The total number of  pizzas that can be made from the given choices is 24.

Step-by-step explanation:  Given that a pizza parlor offers 3 sizes of pizzas, 2 types of crust, and one of 4 different toppings.

We are to find the number of different pizzas that can be made from the given choices.

We have the <em><u>COUNTING PRINCIPLE :</u></em>

If we have m ways of doing one task and n ways of doing the second task, then the number of ways in which we can do both the tasks together is m×n.

Therefore, the number of different pizzas that can be made from the given choices is

N=3\times2\times4=24.

Thus, the total number of  pizzas that can be made from the given choices is 24.

5 0
3 years ago
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