The solution(s) of a system of linear equations give points of intersection of specific lines or planes.
The solution(s) of a system of linear inequalities give areas of intersection wherein any specific pair of points or lines are solutions.
PROCESS-WISE there are little differences between solving systems. However, multiplication and division by negatives reverses the signs in inequalities.
Answer:
we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.
Therefore, the point (0, a) is on the graph of the function f(x) = abˣ
Hence, option (D) is correct.
Step-by-step explanation:
Given the function
f(x) = abˣ
Let us substitute all the points one by one
FOR (b, 0)
y = abˣ
putting x = b, y = 0
0 = abᵇ
FOR (a, b)
y = abˣ
putting x = a, y = b
b = abᵃ
FOR (0, 0)
y = abˣ
putting x = 0, y = 0
0 = ab⁰
0 = a ∵b⁰ = 1
FOR (0, a)
y = abˣ
putting x = 0, y = a
a = ab⁰
a = a ∵b⁰ = 1
TRUE
Thus, we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.
Therefore, the point (0, a) is on the graph of the function f(x) = abˣ
Hence, option (D) is correct.
Answer:
me nhi btaonga AD sab ko bhejta hun
Step-by-step explanation:
