What is the square root of 12383?

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

8 0

The answer is 111.278928823please rate me as the brainliest

Stels [109]3 years ago

5 0

sorry it's such a long answer 111.278928823

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Graphs which present the values on the horizontal axis and the number of times this occurs on the vertical axis are known as wha

Ivanshal [37]

Answer:

The horizontal axis represents TIME

Step-by-step explanation:

In a time-series plot, the horizontal axis represents time, and the vertical axis represents the value of the variable we are measuring. -The values of the variable are plotted at each of the times, then the points are connected with straight lines.

3 0

3 years ago

4|2x+7|=16 x=? and x=?

sammy [17]

4 | 2x + 7 | = 16...divide both sides by 4
| 2x + 7 | = 16/4
| 2x + 7 | = 4

2x + 7 = 4 -(2x + 7) = 4
2x = 4 - 7 -2x - 7 = 4
2x = -3 -2x = 4 + 7
x = -3/2 -2x = 11
x = -11/2

so x = -3/2 and x = -11/2

5 0

4 years ago

In the expansion of (1/ax +2ax^2)^5 the coefficient of x is five. Find the value of the constant a.

DedPeter [7]

Answer:

80x⁴

Step-by-step explanation:

$(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2$

$+ 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5$

$5C_0(\frac{1}{ax})^5(2ax^2)^0 =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1 = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\$