Answer:
Looks like the scale factor is 1/3.
Step-by-step explanation:
<em>(In this dilation, the green image is polygon ABCDE, and the red image is polygon A'B'C'D'E'. The red image is the resulting image after said dilation.)</em>
A scale factor greater than one enlarges an image, and a scale factor between zero and one shrinks an image, so that rules out options 2 (SF = -3) and 3 (SF = 3).
A negative scale factor would end up in an image opposite the center of enlargement, so that eliminates option 4 (SF = -1/3).
So that means that the scale factor is option 1 (SF = 1/3)!
Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
step 1: open brackets n rmb to flip the signs
step 2 (optional): rearrange to make the equation clearer to add/minus
length of 3rd side:
(8x + 3) - (2x + 1) -(5x + 2)
= 8x + 3 - 2x -1 - 5x -2
= 8x -2x -5x +3 -1 -2
= x
Therefore, length of 3rd side is X cm.
---
If perimeter = 75cm,
8x +3 = 75
8x = 75-3
8x = 72
x = 9 cm
Therefore,
1st side = 2(9) +1
= 19 cm
2nd side = 5(9) +2
= 47 cm
3rd side = 9 cm
H(17) = 17
Do you need help with the other 2?
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:
A=πr^2+xy
A=π(2.5)^2+5*15
A=6.25π+75 in^2
A≈94.63 in^2 (to nearest hundredth) so
A≈95 in^2 (to nearest whole square inch)
