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liraira [26]
4 years ago
12

Simplify the following expression.

Mathematics
1 answer:
erica [24]4 years ago
3 0

Answer:

B)  53x + 74

Step-by-step explanation:

(59x + 64) - (6x - 10) = 59x + 64 - 6x + 10

                                = 53x + 74

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Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t
Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0
4 years ago
What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction
Tcecarenko [31]

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} is the expression \frac{2}{k+2}

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0
3 years ago
What is the area of the figure?<br> 10 inches<br> 8 inches<br> 6 inches<br> 16 inches
Ostrovityanka [42]
I’m pretty sure it’s 10 and 16
5 0
3 years ago
What is 63.5 divided by 5 estimating qoutients i need help
Oksi-84 [34.3K]
So basically your gonna regaurd 63.5 as 60 +3.5, 60 is 5*12 and the remaining 3.5 is less than the divisor 5, so it would be the remainder 
anwser is 63.5/5 treat as 60/5+3.5/5
so anwser is 60/5+3.5/5=0.7=12.7
5 0
3 years ago
Discrete Mathematics I
faust18 [17]

ANSWER



The general solution is 86+280n, where n is an  integer



<u>EXPLANATION</u>



In order  to solve the linear congruence;



33x \equiv 38(mod\:280)



We need to determine the inverse of 33 (which is a Bézout coefficient for 33).



To do that we must first use  the Euclidean Algorithm to verify the existence of the inverse by showing that;



gcd(33,\:280)=1



Now, here we go;



280=8\times33+16



33=2\times 16+1



16=2\times 8+0



The greatest common divisor is the last remainder before the remainder of zero.



Hence, the gcd(33,\:280)=1.



We now express this gcd of 1 as a linear combination of  33 and 280.



We can achieve this by making all the non zero remainders the subject and making a backward substitution.



1=33-2\times 16--(1)



16=280-33\times8--(2)



Equation (2) in equation (1) gives,



1=33-2\times (280-8\times33)



1=33-2\times 280+16\times33



1=17\times33-2\times 280



The above linear combination tells us that  17 is the inverse of 33.



Now we multiply both sides of our congruence relation by 17.



17\times 33x \equiv 17\times 38(mod\:280)



This implies that;



x \equiv 646(mod\:280)



x \equiv 86.



Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.



Therefore the general solution is,



86+280n, where n is an  integer

6 0
3 years ago
Read 2 more answers
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