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Wittaler [7]
3 years ago
14

What’s the value of y?

Mathematics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

Step-by-step explanation:

2y=11-3

2y=8

Y=8/2

Y=4

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Nerissa has 5 pink bows, 1 blue bow , and 4 purple bows in a box she will randomly choose 1 bow from the box
Dima020 [189]

Answer:

blue bow

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
2x+4y+2z= -8<br> 5y-2z= 0<br> 4z= -20
kondaur [170]

Answer:

The given solution for the system is x = 5, y = -2 and z = -5

Step-by-step explanation:

Here, the given set of equations are:

2 x + 4 y +2 z = -8

5 y- 2 z = 0

4 z = -20

Now, simplifying each question one by one ,we get:

Simplifying third equation for the value of z:

4 z = -20 ⇒ z  = -20 / 4 = - 5

or, z =  -5

Simplifying second equation for the value of y:

Substitute the value of z  = -5 in (2) , we get

5 y- 2 z = 0    ⇒ 5 y - 2(-5)  = 0

or, 5 y + 10 = 0

or, 5 y = -10

or, y  =  -10/5 = -2

⇒ y = -2

Simplifying first equation for the value of x:

Substitute the value of z  = -5 and y  = -2 in (1) , we get

2 x + 4 y + 2 z = -8  ⇒ 2 x + 4 (-2) + 2 (-5) = -8

or,  2 x - 8 - 10 = -8

or, 2 x = 10

x = 10 / 2  = 5, or x  = 5

Hence, the given solution for the system is x = 5, y = -2 and z = -5

7 0
4 years ago
An object travels 4/5 miles in one-half hour. Waht is its speed in miles per hour?
liubo4ka [24]

So you have to double the numerator of the fraction which is 4 times 2 equals 8 so it’s 8/5 miles per hour or 1.6 mph

8 0
3 years ago
Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th
NeX [460]

As long as Loren drove, the law of motion was

200 = st_1 \implies t_1 = \dfrac{200}{s}

As long as Loid drove, the law of motion was

100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}

So, the total time they took is

t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}

Had Loren driven the whole time, the law of motion would have been

300=st_3 \implies t_3 = \dfrac{300}{s}

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

t_3 = t_1+t_2-0.5

This translates into

\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}

If we subtract 200/s from both sides, we have

\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}

We can simplify the right hand side by summing the two fractions:

\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}

So, we have to solve

\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}

If we cross multiply the denominators, we have

200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0

Which yields the solutions

s=-40,\quad s=50

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0
3 years ago
Read 2 more answers
Their win percentage was 40, WICHTW hally s
xxMikexx [17]

Answer:

The answer is 800

Step-by-step explanation:

just divide 600 divided by 75%

easy

and if that doesn't work idk what will... sorry

3 0
3 years ago
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