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blondinia [14]
2 years ago
9

Car A travels 180 miles in 7 hours. Car b travels 350 miles in 4 hours. Car c travels 584 miles in 15 hours. Which car has faste

st average speed?

Mathematics
1 answer:
alex41 [277]2 years ago
5 0
Car b has the fastest average speed
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Write the equation for the line that goes through point (12, 15) with slope = −2.
pogonyaev

Answer:

y= -2x +39

Step-by-step explanation:

y= mx+b

m is the slope which is given -2

since we don't know b we can solve the rest using the formula y-y1{ m(x-X1(

y - 15 = -2(x-12)

simplify

y-15= -2x +24

y= -2x + 39

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2 years ago
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Given the diagram below, find the measure in degrees of angle b & angle c
kifflom [539]
The answer is B=34,C=68
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3 years ago
Find m angle TUV if m angle TUN=1+38 pi m angle NUV=66^ m angle TUV=105x
ipn [44]

Answer:

m∠TUV = 105

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠TUN = 1 + 38x

m∠NUV = 66°

m∠TUV = 105x

m∠TUV =?

Next, we shall determine the value of x. This can be obtained as illustrated below:

m∠TUV = m∠TUN + m∠NUV

105x = (1 + 38x) + 66

105x = 1 + 38x + 66

Collect like terms

105x – 38x = 1 + 66

67x = 67

Divide both side by 67

x = 67 / 67

x = 1

Finally, we shall determine the value of m∠TUV. This can be obtained as shown below:

m∠TUV = 105x

x = 1

m∠TUV = 105(1)

m∠TUV = 105

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3 years ago
My brother told me he will give me $.25 per day for 10 days OR he will give me $.01 then give me double the following day for 10
NARA [144]

Answer:

you will get more money if he gives you 1 cent per day then doubles it

Step-by-step explanation:

if your brother gives you 25 cents per day, at the end of 10 days you will have $2.50

if he gives you 1 cent per day then doubles it, this will be your daily earnings:

day 1- 0.01

day 2- 0.02

day 3-  0.04

day 4- 0.08

day 5- 0.16

day 6- 0.32

day 7- 0.64

day 8- 1.28

day 9- 2.56

day 10- 5.12

then when you add all of this up, you would recieve 10.23 cents at the end of day 10

4 0
2 years ago
Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!
den301095 [7]

\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}

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3 years ago
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