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masya89 [10]
3 years ago
15

An exterior angle of a regular convex polygon is 40°. What is the number of sides of the polygon?

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

option B

Step-by-step explanation:

Sum of interior angles of a polygon with n sides:

                                                                          = (n - 2 )\times 180

Therefore, Each \ interior \  angle = (\frac{n - 2}{n} )\times 180

Sum \  of \  one \  of \  the  \ interior \  angle \  with  \ its  \ exterior \  angle \  is \  180^\circ

                      [ \ because \ straight \ line \ angle = 180^\circ \ ]

That is ,

Exterior \ angle + Interior \ angle = 180^\circ\\\\40^ \circ + (\frac{n-2}{n}) \times 180  = 180^\circ\\\\40 n + 180n - 360 = 180n\\\\40n = 180n - 180n + 360 \\\\40n = 360 \\\\n = 9

OR

Sum of exterior angles of a regular polygon = 360

Given 1 exterior angle of the regular polygon is  40

Therefore ,

               n \times 40 = 360\\\\n  = \frac{360}{40} \\\\n = 9

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Answer:

The average rate of change is 8.

Step-by-step explanation:

The formula to calculate the average rate of change of a function F(x) is:

\frac{F(b)-F(a)}{b-a}

In this case, F(x) = 0.5x^{2} +5x+9

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You have to evaluate x=2 (which is a in the formula) and x=4 (which is b in the formula) in the function.

In order to obtain F(b) and F(a) you have to replace x=4 and x=2 in the given function:

F(b) = (0.5)4^{2} + 5(4) +9= 37

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Read 2 more answers
What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)
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9514 1404 393

Answer:

  • common denominator: (x² -4)
  • simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

  a² -b² = (a -b)(a +b)

__

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

  \dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}

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