Ask question

Ask question

All categories

3 years ago

8

Isaac And his brother and sister Jake,Rosie was playing on the Xbox one Isaac spend 12x13 dollar on a game jake spend 52x12 in a

game Rosa spend 78x92 who spend the most money from least to high

2 answers:

wolverine [178]3 years ago

7 0

Isaac:12 x 13=156Jake:52 x 12=624Rosie:78 x 92=7,176
Therefore the order is Isaac, Jack, Rosie(Isaac spent not spend)

miss Akunina [59]3 years ago

3 0

Isaac is least then jake then rosa is greatest

You might be interested in

Taylor, Moore, and Jenkins are candidates for public office. It is estimated that Moore and Jenkins have about the same probabil

katrin [286]

Answer:

Taylor = 50%

Moore = 25%

Jenkins = 25%

Step-by-step explanation:

Assuming there are no other candidates and that someone has to win the election, the probabilities of Taylor, Moore, and Jenkins winning the election must add up to 1 or 100%.

$T+M+J = 1\\$

Since Moore and Jenkins have about the same probability of winning, and Taylor is believed to be twice as likely to win as either of the others:

$M=J\\T=2J\\J+J+2J=1\\J=0.25\\M=J=0.25\\T=2*0.25=0.5$

Taylor has a probability of 50% of winning the election.

Moore has a probability of 25% of winning the election.

Jenkins has a probability of 25% of winning the election.

3 0

3 years ago

Is Figure A congruent to Figure B? Explain.

velikii [3]

Yes, because figure B can be obtained from figure A by a series of translations

6 0

3 years ago

A number between 61-107 and are multiples of 3,8,12

Sergeu [11.5K]

72 is the answer you are looking for here

3 0

4 years ago

If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?

Agata [3.3K]

<h3>Given</h3>

A geometric sequence such that ...

$a_2=-2\quad\text{and}\quad a_5=16$

<h3>Find</h3>

$a_{14}$

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

$a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192$

7 0

3 years ago

How to write (1.5 x 10^-4) x (2.5 x 10^3) in scientific notation

maria [59]

<h2>Answer:</h2>

The answer to your question is: (4 x 10^-1)

7 0

3 years ago