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3 years ago

Find the equation for the asymptote y=10/x

1 answer:

7 0

Actually, this graph has two asymptotes: a vertical one and a horiz. one.

Note that we cannot divide by zero. Thus, x = 0 is the vertical asymptote.

Note that as x continues to grow, y tends towards zero. Thus, y = 0 is the horiz. asy.

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100 points

inna [77]

$\huge{ \mathbf{ \underline{ Answer }\: \: ✓ }}$

The sand we need to fill the cylinders is equal to the total volume of the six cylindrical posts .

Given terms ( common for each cylinder ) :

height (h) = 4 ft
radius. (r) = 0.5 ft

$\large \boxed{ \mathrm{volume =\pi {r}^{2} h}}$

$3.14 \times \dfrac{1}{2} \times \dfrac{1}{2} \times 4$

$\mathrm{3.14 \: ft {}^{3} }$

Since volume of each cylinder is equal, so total volume of six cylindrical post :

$3.14 \times 6$

${ \mathrm{18.84 \: ft {}^{3} }}$

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

3 0

3 years ago

Read 2 more answers

A five-sided solid has the numbers 1, 2, 3, 4, and 5. What is the probability of rolling two five-sided number solids and gettin

Umnica [9.8K]

The answer is 1 out of 5

4 0

2 years ago

What is the solution of StartRoot x minus 4 EndRoot + 5 = 2?

Vlad1618 [11]

Answer:

Step-by-step explanation:

$\sqrt{x-4}+5=2 \\\\\sqrt{x-4}=-3 \\\\x-4=9 \\\\x=13$

Hope this helps!

6 0

3 years ago

Read 2 more answers

N triangle ABC (see sketch), AD is the angle bisector of the angle A and BH is the height from side AC. The obtuse angle between

Alex Ar [27]

Answer: C

Step-by-step explanation:

We know that $\angle AHB=90^{\circ}$ , and thus by the exterior angle theorem,

$90^{\circ}+\alpha=4\alpha\\\\90=3\alpha\\\\\alpha=30^{\circ}$

Thus, $\angle CAB=2\theta=\boxed{60^{\circ}}$

8 0

2 years ago

How do you find the minimum value of a quadratic function?

aniked [119]

The minimum value of a function is the place where the graph has a vertex at its lowest point.

There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.

(1) By plotting graph

We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.

(2) By solving equation

The second way to find the minimum value comes when we have the equation y = ax² + bx + c.

If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.

The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.

If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.

After determining that we actually will have a minimum point, use the equation to find it.

6 0

3 years ago