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77julia77 [94]
3 years ago
7

Is a triangle with sides of length 6 ft., 21 ft., 23 ft. a right triangle?

Mathematics
2 answers:
allochka39001 [22]3 years ago
6 0

Yes It is a right triangle

Don't forget to make me the brainiest

Akimi4 [234]3 years ago
6 0
Yes it's a right triangle 

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A self own company charges $40 per month +0.05 cents for each text message sent.Select expression is there a percent of cost in
kondaur [170]
<h3>The monthly cost of cell phone is A  =  40 + 0.005 m</h3>

Step-by-step explanation:

The monthly fixed charges by mobile company = $40

The cost of sending each text message  = 0.05 cents

Now, 100 cents  = 1 dollar

⇒ 1 cent  =$ (\frac{1}{100} )

⇒ 0.05  cent s =$ (\frac{1}{100}  \times 0.05)  =0.0005

Also, the number of text messages send  =  m

So, the cost of sending m text message  = m x ( cost of 1 text )

= m x ( $ 0.0005) = 0.0005 m

Now, Total bill = Fixed rate + cost of m texts

⇒ A  =$40  +  $ 0.0005 m

Hence, the monthly cost of cell phone is A  =  40 + 0.005 m

7 0
3 years ago
Write the ordered pair that describes a point 12 units down from and 7 units to the right of the origin.
emmainna [20.7K]
(-7,-12) s it both down and to the right of the origin
8 0
3 years ago
Read 2 more answers
Solve for x. 8^(x+3)=32
Damm [24]

Answer:

x = -4/3

Step-by-step explanation:

8^(x+3)=32

2^3 = 8

2^5 = 32

3( x + 3 ) = 5

3x + 9 = 5

3x = -4

x = -4/3

Tell me if I am wrong.

Can I get brainliest

4 0
3 years ago
Read 2 more answers
Help me out please will mark you BRAINLIST
melisa1 [442]

Answer:

D. 18.68

Step-by-step explanation:

27\div \frac{5}{3}-6+53\times (\frac{2}{5})^2

Applying PEMDAS as order of operations.

Solving the exponents first [(\frac{2}{5})^2=\frac{4}{25}]

=27\div \frac{5}{3}-6+53\times \frac{4}{25}

Multiplying [53\times \frac{4}{25}=8.48]

=27\div \frac{5}{3}-6+8.48

Dividing [27\div \frac{5}{3}=16.2]

=16.2-6+8.48

Adding and subtracting.

=18.68

6 0
3 years ago
HELP PLEASEEE. I DONT UNDERSTAND
Shtirlitz [24]

Answer:

D

Step-by-step explanation:

So we have the equation:

x^2-6x+58=0

And we want to solve for x.

We can solve it by completing the square.

First, subtract 58 from both sides:

x^2-6x=-58

Divide the b term by 2 and square it:

(-6)/2=-3\\(-3)^2=9

So, add 9 to both sides:

(x^2-6x+9)=-58+9

On the left, the perfect square trinomial pattern. Add on the right. So:

(x-3)^2=-49

Take the square root of both sides:

x-3=\pm \sqrt{-49}

The square root of -49 is 7i:

x-3=\pm 7i

Add 3 to both sides:

x=3\pm 7i

So, our answer is D.

And we're done!

4 0
3 years ago
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