This is an optimization calculus problem where you would need to know a little bit more about the box, atleast i would think. You would just need to use the volume equation of a sphere as the restrictive equation in the optimization problem. Perhaps there is a way to solve with the given information, but i do not know how to.
Answer:
2/√2
Step-by-step explanation:
We are to solve this surd question
2(√3)/√6
2(√3)/√2×3
2(√3)/√2×√3
Divide both by√3
2/√2
We will have to leave the answer in surd form
So the final answer is 2/√2
<h3>Answer:</h3>
Equation of the ellipse = 3x² + 5y² = 32
<h3>Step-by-step explanation:</h3>
<h2>Given:</h2>
- The centre of the ellipse is at the origin and the X axis is the major axis
- It passes through the points (-3, 1) and (2, -2)
<h2>To Find:</h2>
- The equation of the ellipse
<h2>Solution:</h2>
The equation of an ellipse is given by,

Given that the ellipse passes through the point (-3, 1)
Hence,

Cross multiplying we get,
- 9b² + a² = 1 ²× a²b²
- a²b² = 9b² + a²
Multiply by 4 on both sides,
- 4a²b² = 36b² + 4a²------(1)
Also by given the ellipse passes through the point (2, -2)
Substituting this,

Cross multiply,
- 4b² + 4a² = 1 × a²b²
- a²b² = 4b² + 4a²-------(2)
Subtracting equations 2 and 1,
- 3a²b² = 32b²
- 3a² = 32
- a² = 32/3----(3)
Substituting in 2,
- 32/3 × b² = 4b² + 4 × 32/3
- 32/3 b² = 4b² + 128/3
- 32/3 b² = (12b² + 128)/3
- 32b² = 12b² + 128
- 20b² = 128
- b² = 128/20 = 32/5
Substituting the values in the equation for ellipse,


Multiplying whole equation by 32 we get,
3x² + 5y² = 32
<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
Answer:
1/3
Step-by-step explanation:
Slope is rise over run
your rise is 1 (because you only go up one block each time)
your run is 3 ( because you go right three times)
so 1/3
Answer: it was the graph because I got it wrong the first time
Step-by-step explanation: