Answer:
The answer is 434nm
Explanation:
The Rydberg equation is an empirical relationship expressed by Balmer and Rydberg which is stated as:
1/λ = .............................. (1)
where λ is the wavelength, is the Rydberg constant equal to
, n is the transition level number, the subscript f and i are the final and initial levels respectively. Therefore for final transition n = 2 and for initial transition n = 5.
Making substitutions into equation (1), gives
1/λ =
=
=
=
= 2303700
∴ λ =
Converting to nm, we have
λ =
Therefore, the wavelength of the emitted photon is 434nm
