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Alja [10]
3 years ago
12

Calculate the mass of 0.5dm3 of a 2g/dm3 solution of silver nitrate

Chemistry
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

5.6

Explanation:

Because of the gravity of the earth

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What type(s) of bonding would be expected for each of the following materials: brass (a copper-zinc alloy), rubber, barium sulfi
mr_godi [17]

The force of attraction that results in holding of atoms or ions together in a molecule or crystal is said be bonding.  Bond formation can take place by either attraction or transfer of electrons. There are single, double, and triple bonds.  There are many types of bonding namely:

Covalent (sharing of electrons takes place).

Ionic (transfer of electrons takes place).

Metallic (ionized atoms of metals and the sea of electrons around them).

  • Brass (a copper-zinc alloy)

Brass is an alloy of metal that is copper and zinc. Hence, the metallic bonding is present in the brass.

  • Rubber

It is a polymer whose monomer unit is isoprene, which is a covalent compound. The isoprene units are attached in repeated units to form rubber by covalent bonding.

  • Barium sulfide (BaS)

Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.

  • Solid xenon

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  • Bronze

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7 0
3 years ago
Wich of the following is a unit of volume in the english system of mesurement​
ch4aika [34]

Answer:

uhh its gallon

Explanation:

5 0
3 years ago
INFORMATION FOR MY LAST QUESTION THIS IS PART A OF THE QUESTION
Anika [276]

Answer:

The print is so little i cant read it. :( Sorry!

Explanation:

4 0
3 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -> 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
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