Question

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked how many months had passed since their last visit to a dentist. Their responses were as follows: 6 17 11 22 29 Assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program.

Answer 1

Answer:

A 95% confidence interval for the mean number of months elapsed since the last visit to a dentist, is $[5.79063, 28.20937]$

Step-by-step explanation:

We will build a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist. A (1 - $\alpha$) x100% confidence interval for the mean number of months elapsed since the last visit to a dentist with unknown variance and is given by:

$[\bar x -T_{(n-1,\frac{\alpha}{2})} \frac{S}{\sqrt{n}}, \bar x +T_{(n-1,\frac{\alpha}{2})} \frac{S}{\sqrt{n}}]$

$\bar X = 17$

$n = 5$

$\alpha = 0.05$

$T_{(n-1,\frac{\alpha}{2})}=2.7764$

$S = 9.0277$

$[17 -2.7764 \frac{9.0277}{\sqrt{5}}, 17 +2.77644 \frac{9.0277}{\sqrt{5}}]$

A 95% confidence interval for the mean number of months elapsed since the last visit to a dentist, is    $[5.79063, 28.20937]$