All categories

2 years ago

Which of the f-values satisfy the following inequality? f+8≤12 Choose all answers that apply:

Mathematics

1 answer:

Vikki [24]2 years ago

5 0

The answer would be A f = 4

You might be interested in

What is the simplest form of the number 27 2/3

Rashid [163]

The simplest for this answer is 27.66666666..... or 83/3. Hope it help!

8 0

2 years ago

Read 2 more answers

Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)

icang [17]

The equation is $y = \frac{3}{2} x - \frac{11}{2}$

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

So, the midpoint will be $(\frac{-1+7}{2} , \frac{1-5}{2} )\\\\$

= $(3,-2)$

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula $\frac{y_2-y_1}{x_2-x_1}$

The slope is $\frac{-5-1}{7+1}$ = $-\frac{2}{3}$

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of $-\frac{2}{3}$ is $\frac{3}{2}$

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

$-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}$

Thus, the equation becomes:

$y = \frac{3}{2} x - \frac{11}{2}$

7 0

2 years ago

How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?

fredd [130]

The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.

Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.

The difference is 52.73 sq in; the square is larger, the circle smaller.

7 0

2 years ago

To start planning the rooms' floor plans, you draw them each to scale on large sheets of paper. You are going to use the scale 1

Gre4nikov [31]

480 is the answer I just took the test

8 0

2 years ago

What value in place of the question mark makes the polynomial below a perfect square trinomial? 9x2+?x+64

serg [7]

9x² + bx + 64
\/(9x²) = 3x
\/84 = 8
2*3x*8 = 48x
b = 48

4 0

2 years ago

Read 2 more answers