Answer:
They are at the same height at 1.13 seconds.
Step-by-step explanation:
Remark
The rockets are at the same height when f(x) = g(x) [see below] are the same. So you can equate them.
Givens
f(x) = - 16x^2 + 74x + 9
g(x) = -16x^2 + 82x I have changed this so you don't have 2 f(x)s
Solution
- f(x) = g(x)
- -16x^2 + 74x + 9 = -16x^2 + 82x Add: 16x^2 to both sides
- -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x Combine terms
- 74x + 9 = 82x Subtract 74x from both sides
- 74x - 74x + 9 = 82x - 74x Combine
- 9 = 8x Divide by 8
- 9/8 = 8x/8
- x = 1 1/8 Convert to decimal
- x = 1.125
- x = 1.13 [rounded]
Answer:
I think it's the last one. Sorry if I'm wrong
Answer:
The height of the hot air balloon is 1514.54 feet approximately.
Step-by-step explanation:
Consider the provided information.
The angle of elevation from the top of a 95-foot tall building to a hot air balloon in the sky is 76. If the horizontal distance between the building and the hot air balloon is 354 feet, find the height of the hot air balloon
The figure is shown below:
Let the height of the balloon is AD, the height of the building is BC.
Draw a line BE parallel to CD.
Therefore, AD=x+95, BC=95 and BE=CD=354 ft
Now in triangle 
.
The height air balloon is 1419.54+95
=1514.54 ft
Hence, the height of the hot air balloon is 1514.54 feet approximately.
Answer:
1. Three collinear points are R, X, and Q
2. Plane V is a quadrilateral
3. The three segments are PQ, RX, and XQ
4. The two rays are Xr and QS
5. The five lines (each taken alone) are Xr, QS, PQ, RX, and XQ
Step-by-step explanation:
1. Collinear points are points that lie in or can be located on the same line
2) A quadrilateral is a four sided two-dimensional shape
3) A line segment is a line portion between two end points
4) A ray is a line with one end point that extends to infinity in a direction
5) A line is a one dimensional straight geometric figure that extends to infinity in both directions.
