All categories

3 years ago

A wall takes 10 seconds to strike 6.how much time will it take to strike 12?

1 answer:

3 0

I think it is 20 seconds because when you multiply six times x, you get twelve. And in this case, the x equals two. So, because you multiplied two to six, you do the same thing to the ten seconds, which is twenty. Sorry if this is the wrong answer.

You might be interested in

Help me help me help me

Vinil7 [7]

Answer:

40 dollars the answer is 40!!!

6 0

3 years ago

A movies rental company deducts $7 from Serena’s account every month for a year. After 1 year , how much do movie rental fees ch

oksano4ka [1.4K]

Answer:

She's been charged 84 dollars

Step-by-step explanation:

Let's call each month m

if every month it deducts 7 dollars, then to find how much has been charged after a year, we do

-7 * 12 = -84

5 0

3 years ago

This figure is the net

Afina-wow [57]

I wanna say B but i don’t remember i had that question before though

4 0

3 years ago

Read 2 more answers

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago

PLEASE ANSWER ASAP!!!

gregori [183]

Answer:

Step-by-step explanation:

7 0

3 years ago