When looking at wireless channels, there are a couple of variables to keep in mind:
The number of other networks using what channels
The strength of the other networks on other channels
So generally speaking, channels 1, 6, and 11 are used by default. The reason for this is because there isn't any adjacent channel interference when you have all of your networks spread out in that manner. If for example, a network was using channel 3, that network would interfere with the signals one channel 1 and 6, and the bandwidth of those channels would have to be shared amongst all of those networks. This isn't optimal. Ideally you should look for a channel with less hosts who have weak signals. I know that in my area, channel 11 is the best channel to be on, because the hosts using that channel have weak signal strengths, which results in a lesser chance of those signals interfering with mine.
public class JavaApplication82 {
public static void main(String[] args) {
for (int i = 1; i <= 9; i++){
for (int w = 0; w < i; w++){
System.out.print("*");
}
System.out.println("");
}
}
}
This works for me.
Answer:
The output of the given code as follows:
<u>Output: </u>
{"red", "green"}
Explanation:
- In the given code a list is defined, which contains three elements, which are "red, red, and green". In the next step, a string variable "element" is initialized with a value that is "red".
- Then a for loop is declared, that counts list size, and inside the loop and if block is declared, that compares the value list with element variable then it removes from the list.
Answer:
The answer is "O(n2)"
Explanation:
The worst case is the method that requires so many steps if possible with compiled code sized n. It means the case is also the feature, that achieves an average amount of steps in n component entry information.
- In the given code, The total of n integers lists is O(n), which is used in finding complexity.
- Therefore, O(n)+O(n-1)+ .... +O(1)=O(n2) will also be a general complexity throughout the search and deletion of n minimum elements from the list.
