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worty [1.4K]
4 years ago
14

At a birthday party, seven family members share two pizzas equally. what fraction of a pizza does each family member get?

Mathematics
2 answers:
BabaBlast [244]4 years ago
8 0
I think it's 1/3 I think I don't know
pogonyaev4 years ago
6 0
A seventh for each pizza, or 2/14, since there is 2 pizzas.
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2nd question :) please help quick
marysya [2.9K]

Answer:

look id k which ans u want I m telling both

#5 such number could be <em><u>0</u></em> becoz it is not whole integer or positive

#6 there could be many numbers like

8.67676767.....

or

8.111111111111

etc....

4 0
3 years ago
4x^2-9 (Using Grouping Method please)​
elena55 [62]

Answer:

16x square -9

Step-by-step explanation:

4x^2-9=

4x*4x-9

16x square -9

5 0
4 years ago
A number has the digit 3 in the once place and the digit 4 in the tens place.which of these is another way to write this number?
Anarel [89]
The best way will be 40+3
3 0
4 years ago
Read 2 more answers
I dont have that much time<br><br>A<br>B<br>C<br>D​
Masja [62]

Answer:

C or the 3rd one

Step-by-step explanation:

Because you know the amount of rings bought but not how much shirts cost

4 0
3 years ago
Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
4 years ago
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