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sineoko [7]
4 years ago
9

4x^2-9 (Using Grouping Method please)​

Mathematics
1 answer:
elena55 [62]4 years ago
5 0

Answer:

16x square -9

Step-by-step explanation:

4x^2-9=

4x*4x-9

16x square -9

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32 divided by 4x [16x1/2]-2
tresset_1 [31]
64x x [x] -2

Steps
1. Cancel out the greatest common factor

2. Calculate the absolute value

3. Calculate the quotient

4. Calculate the product

5. And then you get your solution 64x x [x] -2
5 0
2 years ago
A<br> .<br> b.<br> 2.<br> L<br> 37°<br> B<br> LABD =<br> LHFG =<br> d.
Lilit [14]
What in the hell is this
3 0
3 years ago
Simplify 5√72 (I don't know how to break down the square root)
marin [14]

Answer:

42.43

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please show ALL work!<br><br> Solve for x: log₂x+log₂(x-6)=4
Vlad [161]
Answer: x = 8

---------------------------------------------
---------------------------------------------

I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)

log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2

Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.

Only x = 8 is a proper solution.

------------------------

You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)

So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed

5 0
4 years ago
A magic square is a square array of numbers arranged so that the numbers in all​ rows, all​ columns, and the two diagonals have
ioda

Answer:

strategies used are : identifying a sub-goal and Guess and check

Step-by-step explanation:

To create a 3 by 3 magic square using nine of the ten numbers

20,21,22,22,23,24,25,26,27,28 and 29

In order to achieve a 3 by 3 magic square table we will pick Nine consecutive numbers out of the ten numbers given and apply the format below

n+1,n-4,n+3,n+2,n,n-2,n-3,n+4,n-1

we will take n = 24

attached below is the magic square

6 0
4 years ago
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