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Goryan [66]
2 years ago
14

Find the solutions to the system; y=x^2-3x-1 and y=8x-1

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
8 0

{x}^{2}  - 3x - 1 = 8x - 1 \\  {x}^{2} - 11x = 0 \\ x(x - 11) \\ x = 0 \: or \: x = 11

When x = 0,
y = 8x - 1 \\ y = 0 - 1 \\ y =  - 1

When x = 11
y  = 8(11) - 1 \\ y = 87
x = 0, y = - 1
x = 11, y = 87

Answer is B.

Hope this helps. - M
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