Find the solutions to the system; y=x^2-3x-1 and y=8x-1

1 answer:

8 0

${x}^{2} - 3x - 1 = 8x - 1 \\ {x}^{2} - 11x = 0 \\ x(x - 11) \\ x = 0 \: or \: x = 11$

When x = 0,
$y = 8x - 1 \\ y = 0 - 1 \\ y = - 1$

When x = 11
$y = 8(11) - 1 \\ y = 87$
x = 0, y = - 1
x = 11, y = 87

Answer is B.

Hope this helps. - M

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