Shawn’s pay is $123 for 20 hours of work. Find hourly wage and then calculate the amount of pay for 31 hours.

Find the slope of the line passing through the points (-2,-2) and (6,-2).<br> slope

kap26 [50]

Answer:

0/8

Step-by-step explanation:

Slope equals y 2 minus y 1 divided by x 2 minus x 1

-2-(-2)/6-(-2)

0/8

4 0

3 years ago

Find the equation of the line in slope-intercept form (-1,-1) and (1,0)

ArbitrLikvidat [17]

Answer:

An equation in slope-intercept form of the line will be

$y\:=\frac{1}{2}x-\frac{1}{2}$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the points

(-1, -1)

(1, 0)

Finding the slope between (-1,-1) and (1,0)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)$

$m=\frac{0-\left(-1\right)}{1-\left(-1\right)}$

$m=\frac{1}{2}$

substituting m = 1/2 and (-1, -1) in the slope-intercept form of the line equation to determine the y-intercept

$y = mx+b$

$-1=\frac{1}{2}\left(-1\right)+b$

$-\frac{1}{2}+b=-1$

Add 1/2 to both sides

$-\frac{1}{2}+b+\frac{1}{2}=-1+\frac{1}{2}$

$b=-\frac{1}{2}$

substituting m = 1/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

$y\:=\frac{1}{2}x+\left(-\frac{1}{2}\right)$

$y\:=\frac{1}{2}x-\frac{1}{2}$

Therefore, an equation in slope-intercept form of the line will be

$y\:=\frac{1}{2}x-\frac{1}{2}$

3 0

2 years ago

Rylan paid a total of $2,961.00, including principal and interest, over an 11-month period, to pay off his credit card. Choose t

bonufazy [111]

Answer: I would go with C

Step-by-step explanation: if correct please mark brainliest

3 0

2 years ago

Rachel and Hugo sorted 265 crayons each box had 10 crayons how many crayons are left?

ryzh [129]

Answer:

20

Step-by-step explanation:

6 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago