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stiv31 [10]
2 years ago
13

16 31 Here is a compound shape made from two rectangles. - 6 cm 4 cm NOT DRAWN 9 cm TO SCALE 12 cm n ek NO ME (a) Calculate the

perimeter of the shape. cm (1 EN UN​
Mathematics
1 answer:
maks197457 [2]2 years ago
3 0

Answer:

Well perimeter is adding up all the sides since it's a rectangle the first one is just 6 + 6 + 4 + 4 = 20 cm

The second would be 9 + 9 + 12 + 12 = 42 cm if this is not an option or if it is wrong let me know and I will try again

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Write this expression in radical form t^-3/4
ZanzabumX [31]
The first thing you should know are properties of exponents to solve the problem.
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 We have then:
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answer  t^-3/4=4^root((1)/(t^3))
5 0
3 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
Brian is solving the equation x squared minus three-fourths x = 5. What value must be added to both sides of the equation to mak
Allushta [10]

Answer:

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Step-by-step explanation:

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Brian mus add 9/64 to boths sides of the equation.

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Find the percentage of vacationers from<br> question 10 who spent between $1500<br> and $2000.
mars1129 [50]

Answer:

The percentage change of vacationers is 33.3 %

Step-by-step explanation:

Given as :

The old value of the vacationers = $ 1500

The new value of the vacationers = $ 2000

Let the percentage variation = x %

Or, x % increase = \dfrac{\tyextrm new value - \textrm old value}{\textrm old value} × 100

Or,  x % increase = \dfrac{\tyextrm $ 2000 - \textrm $ 1500}{\textrm $ 1500} × 100

Or, x % increase = \frac{500}{1500} × 100

Or, x % increase = \frac{1}{3} × 100

Or, x % increase = \frac{100}{3}

∴  x  = 33.3 %

So, The percentage increase change is 33.3 %

Hence The percentage change of vacationers is 33.3 %   Answer

3 0
3 years ago
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