solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
a < -9
Rearrange:
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
5*a+18-(-27)<0
Step by step solution :
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
5a + 45 = 5 • (a + 9)
Equation at the end of step 1 :
Step 2 :
2.1 Divide both sides by 5
Solve Basic Inequality :
2.2 Subtract 9 from both sides
a < -9
Answer:
The degree is 6, and the zero is 0
Step-by-step explanation:
Hope this helps! :) ~Zane
P.S. sorry if im wrong with the zero one
Answer: The equation in slope-intercept form is y=2x-11
Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.
Hope this helps!
Step-by-step explanation:
y is 130° too because it's an alternative angle love
