Answer:
Explanation:
The following pseudocode for this method using operations of the ADT list would be the following
swap(aList, indexI, indexJ) {
initialize temp_variable = Retrieve(indexI, aList)
Insert(Retrieve(indexJ, aList), indexI, aList)
Insert(Retrieve(indexI, aList), temp_variable, aList)
}
This code basically saves the aList index of i , into a temporary Variable. Then it sets the aList index of i to the value of the element in index of j. Then it does the same for the index of j with the tem_variable. If we assume that the indexes of i and j exist, then it can crash our entire program if those indexes are missing from the list when we try to access them.
Answer: 8.1 msec.
Explanation:
If we are told that we have a transmission link of sending 10 Mbits in one second, setting up a direct proportion, we can find out how much time is needed to send 4096 bits along the same channel, as follows:
10⁶ bits = 1 sec
4096 bits = x ⇒ x = 4096 bits. 1 sec / 10⁶ bits = 4.1 msec.
As we have 4 msec of latency between sender and the receiver, we need to add these 4 msec to the transit time, so we have a total message transmission time of 8.1 msec.
Answer:
Right-click the style in the Quick Styles Gallery, and select the Remove from Quick Style Gallery option.
Explanation:
I would go with text. but I'm not 100% certain