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zalisa [80]
3 years ago
11

Suppose a 4096 bit message is sent along a 10Mbit/sec transmission link. Suppose that the latency between the sender and the rec

eive is 4 milliseconds. What is message transmission time?
Computers and Technology
1 answer:
umka21 [38]3 years ago
8 0

Answer: 8.1 msec.

Explanation:

If we are told that we have a transmission link of sending 10 Mbits in one second, setting up a direct proportion, we can find out how much time is needed to send 4096 bits along the same channel, as follows:

10⁶ bits = 1 sec

4096 bits = x  ⇒ x = 4096 bits. 1 sec / 10⁶ bits = 4.1 msec.

As we have 4 msec of latency between sender and the receiver, we need to add these 4 msec to the transit time, so we have a total message transmission time of 8.1 msec.

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Answer:

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public class  num6{

   static int getTestScores(){

       System.out.println("Enter the Score");

       Scanner in = new Scanner(System.in);

       int score = in.nextInt();

       return score;

   }

   static double calcAverage(int score1, int score2, int score3){

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   }

   static void displayAverage(double ave){

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   public static void main(String[] args) {

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       int num2 = getTestScores();

       int num3 = getTestScores();

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       //Calling displayAverage

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   }

}

Explanation:

  • Using Java programming Language
  • Create the four methods
  • getTestScores() Uses the Scanner Class to receive an in variable and return it
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  • displayAverage() Accepts a double and prints it out with a concatenated string as message
  • In the Main Method, getTestScores is called three times to obtain three numbers from the user
  • calAverage is called and handed the three numbers
  • printAverage is called to output the calculated average
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