Complete the recursive formula of the arithmetic sequence -15, -11, -7, -3,...−15,−11,−7,−3,...minus, 15, comma, minus, 11, comm
o-na [289]
Answer:
c(1) = -15
c(n) = c(n - 1) + 4
Step-by-step explanation:
Given arithmetic sequence is,
-15, -11, -7, -3...........
Common difference between each successive and previous term is,
d = -11 - (-15)
= -11 + 15
= 4
Since recursive formula of the arithmetic sequence is represented by,
a₁ = First term of the sequence
a(n) = a(n - 1) + d
where a(n) is the nth term and a(n-1) is the previous term of the nth term.
Form the given sequence,
c₁ = -15
c(n) = c(n - 1) + 4
650 because they took away two zeros to get 65,000 so you take two zeros away from 65,000 to get 650
Answer:
1.60$
Step-by-step explanation:
first, we have to figure out haw many times 0.75 goes into 12
pretty sure you just want the answer to this and not me to explain the whole thing so:
if you multiply 0.75 by 16 you get 12.
16x0.10= 1.6
so her mother gave 1.60$
R = sqrt(3,6^2+(11/2)^2) = 6,6
Answer:
A. 34; B. 40. D. 88
Step-by-step explanation:
The rule is, "multiply by six and subtract two."
So, if we add two to the number, it should be evenly divisible by 6.
We can check each number.
A. 34 + 2 = 36; 36/6 = 6. TRUE.
B. 40 + 2 = 42; 42/6 = 7. TRUE.
C. 55 + 2 = 57; 57/6 = 9½. False.
D. 88 + 2 = 90; 90/6 = 15. TRUE.
E. 119 + 2 = 121; 121/6 = 20⅙. False.
The numbers that satisfy the rule are 34, 40, and 88.
