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mafiozo [28]
3 years ago
9

Billy stacked 6 pieces of wood on top of one another if each piece was 3/4 of foot tall how tall was his pile

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
The answer would be 4 1/2

Step 1. Multiply 3/4 by 6/1 to get = 18/4
Step 2. Simplify 18/4 to get 4 1/2
—————————————————————————
How to simplify:

Ex: 18/4

See how many times 4 can go into 18.

「divide 4 and 18」

TIP: Always add a 1 under a single number like 3/4x6 change the 6 to: 6/1

|Questions are welcomed|
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Answer:

(6x+12y)

Step-by-step explanation:

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3 years ago
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Which expression is equivalent to the following complex fraction?
Virty [35]

Answer:

  \dfrac{-4x+7}{2(x-2)}

Step-by-step explanation:

Write the terms of numerator and denominator using a common denominator.

  \dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}}=\boxed{\dfrac{-4x+7}{2(x-2)}}

7 0
3 years ago
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If f(1) = 6 and f(n) = f(n − 1) +3, then f(7) =<br> (1) 10 (2) 24 (3) 15<br> (4) 18
Juliette [100K]

Answer:

24

Step-by-step explanation:

f(n) = f(n − 1) + 3

if n = 7 => f(7) = f(7-1) + 3 = f(6) + 3

if n = 6 => f(6) = f(6-1) + 3 = f(5) + 3

if n = 5 => f(5) = f(5-1) + 3 = f(4) + 3

if n = 4 => f(4) = f(4-1) + 3 = f(3) + 3

if n = 3 => f(3) = f(3-1) + 3 = f(2) + 3

if n = 2 => f(2) = f(2-1) + 3 = f(1) + 3

if f(1) = 6 then f(2) = 9

f(3) = 12

f(4) = 15

f(5) = 18

f(6) = 21

f(7) = 24

3 0
3 years ago
An evergreen nursery usually sells a certain shrub after 7 years of growth and shaping. The growth rate during those 7 years is
Ne4ueva [31]

Answer:

( 0.6 t^2 + 3t + 11 ) cm

Step-by-step explanation:

dh/dt = 1.2t + 3

at t = 0, h = 11 cm

(a)

dh / dt = 1.2 t + 3

dh = (1.2 t + 3) dt

integrate on both sides

h = 0.6 t^2 + 3t + c    .... (1)

where c is the integrating constant

put t = 0

11 = c

Put in equation (1) , we get

h = ( 0.6 t^2 + 3t + 11 ) cm

Thus, teh height of tree after t years is given by

( 0.6 t^2 + 3t + 11 ) cm.

3 0
3 years ago
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KATRIN_1 [288]

Answer:

6²-3²

36-9

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5 0
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