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3 years ago

Billy stacked 6 pieces of wood on top of one another if each piece was 3/4 of foot tall how tall was his pile

1 answer:

4 0

The answer would be 4 1/2

Step 1. Multiply 3/4 by 6/1 to get = 18/4
Step 2. Simplify 18/4 to get 4 1/2
—————————————————————————
How to simplify:

Ex: 18/4

See how many times 4 can go into 18.

「divide 4 and 18」

TIP: Always add a 1 under a single number like 3/4x6 change the 6 to: 6/1

|Questions are welcomed|

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Josh is putting up a fence around a garden that is next to a wall. He only has 54 feet of fence and the length of the garden mus

vova2212 [387]

Answer:

Length = 12 feet

Width = 30 feet

Step-by-step explanation:

Let l be the length of the garden and let w be the width:

We have system of equations

2w + l = 54

l = 2w + 6

We substitute 2w + 6 for l

2w + 2w + 6 = 54

4w + 6 = 54

4w = 54 - 6

4w = 48

w = 48/4

w = 12 feet

Width(w) = 12 feet

We find the Length

l = 2w + 6

l = 2(12) + 6

l = 24 + 6

I = 30 feet

7 0

2 years ago

Read 2 more answers

Determine the greatest common factor of 28xy^9z and 32x^2y^7z

RSB [31]

Answer:

GCF = 4xy⁷z

Step-by-step explanation:

Do Prime Factorizations for each term and select only those terms common to each:

28xy⁹z = 2·2·7·x·y·y·y·y·y·y·y·y·y·z

32x²y⁷z = 2·2·2·2·2·x·x·y·y·y·y·y·y·y·z

GCF = 2·2·x·y·y·y·y·y·y·y·z

GCF = 4xy⁷z

5 0

2 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

2 years ago

Help me please I'm terrible at math

mr_godi [17]

Answer:

Step-by-step explanation:

ok first you make a equation which is 2x+1+5x-14

then you combine like terms so 2x+5x= 7x and -14+1=-13

so now the equation is 7x-13

but i need to know the full length of AC to finish it

3 0

2 years ago

Suppose that 95% of the fasteners pass the initial inspection. Of those that fail the initial inspection, 20% are defective. Of

hichkok12 [17]

Answer

Step-by-step explanation:

Let x be the fasteners

95% of x passed, and 5% of x failed

20% of the 5% which failed are defective, remaining the 80% of the failed 5%.

Now 40% of this 80% of the 5% which failed are scrapped, meaning only the remaining 60% passed second inspection.

Thus

a). The proportion ;

60% of 80% of 5% of x

mathematically

= 60/100 × 80/100 × 5/100

= 0.024 or 2.4%

b) initially 95% passed and later on 2.4% pass again. Therefore total that passed = 95%+2.4%=97.4%

c) probability that it passed on first inspection is 95/100

Percentage that went through recrimping = 80% of 5% = 80/100 × 5/100 = 1/25 or 0.04 or 4%

Thus probability of passing and not going through recrimping

= 1 - (1/25) = 0.96 or 96%

7 0

2 years ago