Answer:
Step-by-step explanation:
Triangle FEG is a right angle triangle.
From the given right angle triangle
GE represents the hypotenuse of the right angle triangle.
With ∠E as the reference angle,
EF represents the adjacent side of the right angle triangle.
GF represents the opposite side of the right angle triangle.
To determine FG, we would apply Pythagoras theorem. It is expressed as
Hypotenuse² = opposite side ² + adjacent side²
Therefore,
13² = 5² + FG² = 25 + 169
169 = 25 + FG²
FG² = 169 - 25 = 144
FG = √144 = 12
To determine tan E, we would apply trigonometric ratio
Tan θ = opposite side/adjacent side. Therefore,
Tan E = 12/5
Tan E = 2.4
Y = x + 3 is the answer
the y-intercept is 3, so the answer should have a "+ 3" in it
when you are trying to determine the gradient (the x), you can use two methods
first method:
picture/sketch the line. If the line is going upwards (from left to right), it's positive. If the line is going downwards (from left to right), it's negative. However, this method only works for this question, you should try using the second method more
second method:
use the formula: (y - y) / (x - x)
So, you use the y from one of the brackets and subtract the y from the other bracket. Then, you put it over the x ,from the same bracket as the first y, and subtract the x from the second bracket. If you are confused, look at the picture. (Sorry for the messy explanation)
Answer:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above, let μ represent the average test scores for the teaching methods:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)