A quarter, two dimes, and two pennies.
Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2

Dividing both sides by 7

Putting y=7 in Eqn 1

Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
Not enough information given
Basically subtract 59 from 709 which is 650 , halve 650 which is 325 and then add 59 to the other 325 that u have to add to the first 325 to make 650 so
709-59= 650
650\2= 325
325 + 59= 384
So 384 cheeseburgers were sold and 325 hamburgers
384+325= 709
Solution :
Given data :
The mean length of the steel rod = 29 centimeter (cm)
The standard deviation of a normally distributed lengths of rods = 0.07 centimeter (cm)
a). We are required to find the proportion of rod that have a length of less than 28.9 centimeter (cm).
Therefore, P(x < 28.9) = P(z < (28.9-29) / 0.07)
= P(z < -1.42)
= 0.0778
b). Any rods which is shorter than
cm or longer than
cm that re discarded.
Therefore,
P (x < 24.84 or 25.16 < x) = P( -59.42 < z or -54.85)
= 1.052