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3 years ago

What is an equation of the line that passes through the points (-4, -1) and (3,-8)?

Mathematics

1 answer:

Kaylis [27]3 years ago

6 0

Answer:

y=-x-5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-1))/(3-(-4))

m=(-8+1)/(3+4)

m=-7/7

m=-1

y-y1=m(x-x1)

y-(-1)=-1(x-(-4))

y+1=-1(x+4)

y+1=-x-4

y=-x-4-1

y=-x-5

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Answer:

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Step-by-step explanation:

We have a rectangular blanket, that has a diagonal that measures h=7.21 feet.

The two sides of the rectangle a and b can be related to the diagonal h by the Pithagorean theorem:

$a^2+b^2=h^2$

Then, we can express one side in function of the other as:

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A graph of values of a and b is attached.

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3 years ago

#20 four times the sum of number. and 15 is a least20. Let X represent the number. :find ball possible values for X

gayaneshka [121]

For this case what we have to take into account is the following variable:
x = represent the unknown number
We now write the following inequality:
"four times the sum of number and 15 is at least 20"
4 (x + 15)> = 20
We clear the value of x:
(x + 15)> = 20/4
(x + 15)> = 5
x> = 5 - 15
x> = - 10
The solution set is:
[-10, inf)
Answer:
all possible values for X are:
[-10, inf)

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